The Mass of M87*
And the foundations of the wall of the city were garnished with all manner of precious stones. The first foundation was jasper; the second, sapphire; the third, a chalcedony; the fourth, an emerald; The fifth, sardonyx; the sixth, sardius; the seventh, chrysolite; the eighth, beryl; the ninth, a topaz; the tenth, a chrysoprasus; the eleventh, a jacinth; the twelfth, an amethyst.(Revelation 21:19-20) KJV
Using the Inverse Square law, if a body with the mass of the Sun orbits at a distance of 1 AU, we divide the mass of the sun by the square of the distance to M87* which we estimate to be 17,364 light years.
According to the mainstream science narrative (SciPop):
M87* contains 6.5 billion solar masses. One solar mass is equivalent to the mass of our Sun, approximately 2E+30 kilograms.
1.9E+30 x 6.5E+09 = 1.24E+40 kg– NASA Jet Propulsion Laboratory
In the SciPop paradigm the assumption that gravity is a property of mass has the effect of causing objects that are further away to be more massive. Ironically this is the exact opposite of Newton’s inverse square law, even though it is, technically, Newton’s Paradigm. Here’s the thing: The mass of M87* is a factor of its distance from the Earth, it’s not derived from the Star Trek narrative of SciPop.
Here’s how it works: If we decide that a minute speck in the night sky is a distant sun, it must have a mass at least equivalent to the sun. When a more powerful telescope is available which shows what looks like a cloud of glowing dust beyond it, we have a problem. Since we decided that the star is a sun, then we have to imagine that every particle in the dust cloud is also a sun. We can estimate that there may be a billion particles in the dust cloud. This means that our cloud of glowing dust has the mass of one billion suns. We call our cloud of glowing dust a galaxy.
When a more powerful telescope becomes available which shows what looks like another cloud of glowing dust beyond the first cloud of glowing dust we have another problem. Now we have to imagine that every particle in the further dust cloud is a galaxy. If we estimate that there are one billion particles in the further dust cloud, and we have to give each particle the mass of one billion suns, then the mass of the further dust cloud is a quadrillion suns. We call this a globular cluster.
So what happens when we see a black speck silhouetted against some glowing gas beyond that? This is the curse of the SciPop paradigm: the geometry of despair.
Inverse Square Unfiltered
In Matty’s Paradigm we use the uncut, unfiltered version of the inverse square law. Straight out of the bottle with no additives of fake ingredients. The center of gravity for the cosmos is at the center of the Earth. The field emitted from it causes a body to have attractive force proportional to its mass and inversely proportional to the square of its distance from the source.
Can we calculate a Matty’s Paradigm mass for M87*? Here’s what we have to consider:
- The mass of the Sun isn’t 1.9E+30 kg.
- That value has to be multiplied by a factor of 9.87E-12 (Matty’s Constant),
- This gives the mass of the Sun to be 1.88E+19 kg.
- Likewise distance is different:
- The Earth/firmament radius is approximately 1,736,441 light years.
- THEREFORE M87* can’t be 53.49 million light years away.
- Let’s say it’s half-way between the Earth and the firmament,
- say 868,220 light years away.
- How massive is M87*?
There’s some complicated math used to calculate this number which involves Kepler’s 3rd Law of Planetary Motion and Newton’s Law of Universal Gravitation, but we can do a simple hack to get a value. The first thing we have to do is convert light years to AU to get a distance to M87* that we can use.
Distance to M87* (convert LY to AU)
|Light Years (LY)||Astronomical Units (AU)|
The reason for creation is the manifestation of sentient life with free will.– The Reason for Creation
Using the inverse square law to calculate the mass of M87*
Mass of M87* (50% of the distance to the firmament)
|Distance to M87* [AU] (d)||3.15E+10|
|Mass of the Sun [kg]||1.88E+19|
|Mass of M87* [kg]||1.88E+19/9.9E+20=||0.02|
Is M87* 0.02 kg?. Obviously M87* is closer than our original estimate of half-way to the firmament. Let’s try something smaller, like 1% of the distance.
Mass of M87* (1% of the distance to the firmament)
|Distance to M87* AU||6.29E=08|
|Mass of the Sun [kg]||3.96E+17|
|Mass of M87* [kg]||1.88E+19/3.96E+17=||47.47|
At 1% of the distance to the firmament, 17,364 light years, M87* is about 50 kg. If it has the nature of something similar to Black Onyx then we can calculate its approximate size. We’ll work on that tomorrow.
Planetary Body Mass Values
|Body||Old Mass [Kg]||Matty’s Constant||New Mass [Kg]|
- Call upon the name of Jesus Christ,
- believe in your heart that God raised him from the dead,
- confess your sin.
Read through the Bible in a year
|Reading plan||April 25|
|Linear||2 Chronicles 13-15|
|Chronological||1 Chronicles 3-5|